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51y-y^2-518=0
We add all the numbers together, and all the variables
-1y^2+51y-518=0
a = -1; b = 51; c = -518;
Δ = b2-4ac
Δ = 512-4·(-1)·(-518)
Δ = 529
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{529}=23$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(51)-23}{2*-1}=\frac{-74}{-2} =+37 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(51)+23}{2*-1}=\frac{-28}{-2} =+14 $
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